Nimrod 7 wrote: » (10, 5) and (38, 5) I think.
Aspiring wrote: » If you have the DEB mock on hand see Question 6A. That's exactly how Theorem 13 would come up I'd say.
Nimrod 7 wrote: » You don't even have to do any work for it tbh Wasn't y just 100-23? And A was just looking at the equation and realising y =A. Yeah, that's the one. I think the corollary is just the angles on the same arc bit.
Isitthough? wrote: » how did you get that? I said y=5 and then they gave you f(x) so I let them equal to see where they intersect used -b but I got weird values..Did I do it right or what?
Rbrtmry wrote: » There's a website that shows you how to do all of the costructions step by step if anyone wants. Just type "Leaving cert geometry constructions" into google and it comes up. I'd post a link but i'm not allowed do that for some reason.
Maths Help Needed wrote: » Can somebody help me please, what are the 3 theorems everyone is talking about ? Thanks in advance!
jellytots95 wrote: » I think they're the three ones at the end of geometry.. They're: If three parallel lines cut off equal segments on some transversal line, then they will cut off equal segments on any other transversal Let ABC be a triangle. If a line XY is parallel to Bc and cute AB in the ratio s:t, then it also cuts AC in the same ratio If two triangles are similar, then they're sides are proportional in order
Maths Help Needed wrote: » Thanks very much for the reply do you know what number theorems they are ? Thanks once again
jellytots95 wrote: » 11, 12 and 13 I think
onethreefive wrote: » Maths is driving me crazy. Failed paper one i think and trying my hardest to bring it up to a pass. Can someone please tell me how to construct a perpendicular bisector of a triangle. I'm doing the circumcircle construction.
miissjuly wrote: » You're all going to PASS/get the grade you want. Don't worry. Focus on paper 2!
onethreefive wrote: » I'm on the verge of throwing my maths book out the window. I've spent over half an hour trying to get the perpendicular bisector of a triangle :'( Thanks for the video it helped but I'm not sure what to do for the second line if that makes sense
Hotale.com wrote: » I don't think that question makes sense. "Bi" means two, a triangle has three sides... Unless they want you to split the area? I think to do that you need to split the altitude or something... I'm doing all my P2 study tomorrow.. :P
Ompala wrote: » Off the top of my head... perpendicular bisector refers to splitting one side of a triangle into two equal lengths
Hotale.com wrote: » The question must be worded terribly so, it's "perpendicular" to only one side and you're not even bisecting the triangle if that's the case.
Ompala wrote: » I don't actually know what the question is,, just remember the terminology. Now you have me thinking, how do you bisect a triangle? Split it into two parts of equal areas? Surely there are infinite ways to do that...
