her0fire wrote: » 2 theorems in consecutive years has never happened so don't count on pythagoras to come up. Anyone know how to do paper 1 Q 2 ( c ) ? It was the one with the sets and there was one other question, it was express t in terms of s and r
Indiego wrote: » for q2 c, (this is really hard to explain btw, so sorry if i make no sence ), but, for part one, where you have to find the minimum value of #(PUQ)', it means you have to find the smallest possible number that would work in the part of the venn diagram outside of P and Q
cantanstrophe wrote: » This almost caught me out - in the frenzy of getting the paper, I missed the apostrophe, and answered the question differently, but I changed it soon afterwards :pac:
Indiego wrote: » for q2 c, (this is really hard to explain btw, so sorry if i make no sence ), but, for part one, where you have to find the minimum value of #(PUQ)', it means you have to find the smallest possible number that would work in the part of the venn diagram outside of P and Q, to do this, you can assume that the 16 in P, and the 6 in Q and not part of the intersection, and that P and Q have nothing in the intersection, meaning that P + Q = 16 + 6, which is 22, meaning that the leftover 8 (30-22) would be #(PUQ)'. for part two, you have to find the maximum value of #(PUQ)', meaning you have to find the largest possible number that would make sence in the part of the venn diagram outside of P and Q, and still add up to 30. To do this you can assume that the 6 in Q is also a part of P, meaning it would be in the intersection, meaning # P + Q = P (because Q is part of P) would be 16 only. This means that #(PUQ)' would be 30 - 16, which is 14. Did that make sense? for part three, you have to proove that u = p + x, x being the largest possible number outside of P and Q in the diagram, which mean you can assume its the same situation as in part (ii), where Q is also a part of P, this would mean that u = x - q + p + q, or, u = p + x for the other question, t^2 - s = r, this is how you do it: t^2 - s = r t^2 = r + s (move s across the equal sign and change the sign) t = (sqrt) r + s (find the square root of both sides, meaning that t^2 becomes t, and r + s becomes (sqrt) r + s Hope I helped
her0fire wrote: » Was 2% levy, was that to find the 2% of 40,000?
Desire. wrote: » Yeah, 2% of her gross income.
her0fire wrote: » Would you then add that on top of the tax she has to pay and minus it from her gross income to get the answer?
CradBear wrote: » My maths teacher said that theorem 7,5 and 4 or 3 should be coming up this year :pac:
ohdechertig wrote: » For question 3(a), I forgot to square root the t, so I left it as t^2 = r+s. What would I get out of 10?
phenomenale wrote: » Can deductions be asked in the proofs or is is just the 10 theorems?
Slow Show wrote: » I was always under the impression you wouldn't have to be asked to prove the deductions, you'd just need to know what they mean...
Desire. wrote: » 2008, Question 4, Part B, ii -- "Prove that a line through the centre of a circle perpendicular to a chord bisects the chord."
Colm! wrote: » Huh? That's a theorem, Theorem 8 on the syllabus.
scipsss wrote: » Eh you all might think this is strange but i don't know what pythagorous's theorem is ? i thought it was like h squared + r squared = l squared or something like that ?
buyer95 wrote: » Does anyone know like the key theroems to know? Like what are likely to be asked... I dont know all of them that well and I'm kind of panicking now, no time to learn them all... Any tips?