watty wrote: » We are somewhat west. Here Midday is more like 1:20. It would be 1pm at Greenwich London.
Sam Russell wrote: » You are looking for 28.2 deg east of south. 28.2/360*24*60 minutes before midday. 112.8 mins. Midday is 1 pm summer time. So sun is above the satellite at 11.07 am.
sesswhat wrote: » I realise this is all of little value to the OP who would be much better off watching Tony's video
sesswhat wrote: » The calculations above only apply if you are at the North Pole. If you take a central location in Ireland, say Athlone, the azimuth to the satellite is 137.7 deg, or 42.3 deg east of south. Today, the sun shared this angle at just after 11.34. I realise this is all of little value to the OP who would be much better off watching Tony's video
Sam Russell wrote: » You are looking for 28.2 deg east of south. 28.2/360*24*60 minutes before midday. 112.8 mins.
Apogee wrote: » All of this is academic
Apogee wrote: » If I'm not mistaken, you're assuming that the OP is living on the Greenwich Meridian, as otherwise Astra 2 is not "28.2 deg east of south".
sesswhat wrote: » Even on the Greenwich Meridian, as you move away from the North Pole, the angle will be greater until you reach the equator, where it will be 90 degrees.
Apogee wrote: » The angle to what?
sesswhat wrote: » Only at the North Pole is this angle 28.2 dgrees.
Tony wrote: » Which is really hard to find as a compass does not work at the North pole ( before some else says it, the satellite is below the horizon anyway )
sesswhat wrote: » And I have a very tall periscope to put the dish on
Apogee wrote: » I can't see where you're getting 90 deg from unless you're on about elevation? The azimuthal bearing is measured relative to the centre of the earth's core. There are small corrections that are taken into account depending on your location on the surface of the planet e.g. a 3 degree orbital spacing isn't really a 3 degree spacing depending on the location of the observer. I dig out the reference and post a scan of it.
28.2/360*24*60 minutes before midday. 112.8 mins.
sesswhat wrote: » It's nothing to do with elevation. At the point where the Greenwich meridian crosses the equator, the satellite at 28.2 E, along with many others, is due east along the equator, or 90 degrees east of south. Sam, the method you used originally could be perfect if the sun was always over the equator. You worked out how long it would take for the sun's position to change from a longitude of 28.2 degrees (same as the satellite) to a longitude of 0 degrees (due south, or midday, at Greenwich). Because midday at greenwich is 1pm summer time, the sun was at the same longitude as the satellite at 11.07. However, as you point out, it is only during an equinox that the sun is over the equator all day. At other times, being at the same longitude does not mean it will appear to be directly over the satellite (unless you are looking at them from the Poles). In summer the sun is over a point further north and so at 11.07 it is a bit to the left of the satellite as we look at it. Yesterday it took until 11.34 to 'catch up'.
sesswhat wrote: » It's nothing to do with elevation. At the point where the Greenwich meridian crosses the equator, the satellite at 28.2 E, along with many others, is due east along the equator, or 90 degrees east of south.
Apogee wrote: » I see what you mean. I thought initially you were on about setting elevation for a polarmount on the equator. The best definition I can cobble together is a planar angle of 28.2 degrees east of the plane which passes from the centre of the earth through the Greenwich meridian.