Cohen Melted Pushcart wrote: » Partially. You have worked this out as though it were an arithmetic sequence (adding a certain amount every term). It was actually a geometric series (multiplying by a certain amount every time). I have never seen someone mix the two up before so I don't know how that will affect your marks.
neiler987 wrote: » no thats nt what i done tho ur probably right !? heres wat i done... 9=4th term 243=7th term .. 9+78=87 87=5th term 87+78=165 165=6th term 165+78=243 243=7th term !! common difference = 78 so i found de 1st nd 2nd terms by goin backwards frm de 5th term that was given ... 9-78= -69 69=3rd term 69-78= -147 =2nd term.... -147-78= -225= 1st term so common ratio = 2nd term divide by 1st term -147 divide by -225 = 0.653thats gotta be so wrong isin it lol ? part C (ii) find 1st term... -225 = 1st term
Conor108 wrote: » I was really stuck on q5 part c. THINK I got it but just by messing with my calculator in the last 10 mins. T4 = 9 -> T5 = 9(3)= 27 -> T6 = 27(3) = 81 -> T7 = 81(3) = 243 Therefore R=3
0.M.GXX wrote: » Hello .. ok i dont know if ill get any marks for this but i worked this out logically.. i just started multiplying 9 by random numbers... example 9x3=27,27x3=81,81x3=243 and i knew this was correct considering it was the 7th term... how did you get on in q5 part a???
Victoria. wrote: » I just realised I forgot to put the model of my calculator down on the front of the exam booklet. Was so stressed after geography Does anyone know if it is a big problem?
Conor108 wrote: » Yay! I got those! Except for part i I just said 10 seconds. How many marks lost is that d'ya reckon?
Cohen Melted Pushcart wrote: » Q7 (c) i: 0 and 10 seconds ii: 20 m/s squared (or m/s/s) iii: T>5. For this one you needed to find where DV/DT was 0 (the turning point) and as the curve (of acceleration) began rising and ended falling, anything after 5 was negative.
Mau5 wrote: » I got €7444 for it I think... could be very wrong though, im terrible at maths!
neiler987 wrote: » anyone do question 5 c (i) ?.. where u had ti find the common ratio which is usually 2nd term divide by 1st term bu they gave the 4th nd 7th term think i worked out de 1st nd 2nd term wrong tho or did u not need ti find 1st nd 2nd term ????? ..any1 help on this please ?
PARARORY wrote: » For the q7 about speed / acceleration i got exactly what you've all been saying.And fridayswell i did the same as u - putting both 0 and 8 seconds down as it did say timeS
MariaBabii wrote: » I got : (i) 10sec (ii) 20m/s (iii) I just said 8secs? becomes it says become negative, so i doubt that its a negative answer ... Just a thought!
doc_17 wrote: » Did anyone do c (i) like this? 1.05 x 1.05 x 1.05 = 1.1576 8682/1.11576 = 7500
FridaysWell wrote: » (i) Times were speed = 96 0 secs and 10 secs (ii) Acceleration = 20 m/s/s (I didnt put the M/s/s in will I lose marks?) (iii) -8 (sounds very wrong)
cork*girl wrote: » I got (i) 7 :L Hopefully I will get 3marks (ii) I got 20 aswell (iii) I got 6.. I think -8 was the number that came out in the calculator to say that it was negitve when you use 6. Not sure, fingers crossed. I beg you God! Please let me pass maths !!
cork*girl wrote: » If ya got 7444 instead of 7500 would ya get about 7 marks or just an attempt mark of 3?? what did people get for answers in 7 (c) ?
SirDarren wrote: » To everybody that got €7444 for their answer, that's because you all multiplied the 8682 by 0.95 three times thinking that was taking away 5% compound interest each time. Hopefully that'll help some people out
neiler987 wrote: » thanks fridays well yeah coz i got de 3.78 from 2+(sqaure root) of 3= 3.78 so im gussin thats de value of c than jus used the formula ..guessin its only worth 5 marks tho it all adds up in de end !
