GTTDI GOD wrote: » 7 * (4 + 3) * (8 + 6 - 5) = 441 4, 6, 7, 8, 9, 10 375
wally79 wrote: » 2 2 4 5 6 10 337
GTTDI GOD wrote: » 5 * 6 + 4 = 34 * 10 - 2 = 338 1, 3, 5, 5, 8, 10 527
Wanderer2010 wrote: » 8*(5+1)=48+5=53*10=530-3=527 100 4 5 5 9 1 633
wally79 wrote: » (100+4)*(5+1)=624+9=633 1 2 4 5 7 8 369
Notoldorwise wrote: » (5*8)+1=41*(7+2)=369 2 3 5 7 8 25 831
Wanderer2010 wrote: » 7 5 9 10 1 4 729
brophya2007 wrote: » (7+1)*9*10=720 720+4+5 = 729 9 1 3 4 5 25 622
wally79 wrote: » (4+1)*5*25=625-3=622 3 3 5 6 7 10 653
Wanderer2010 wrote: » (6+5)*(3+3) = 66*10 =660-7 = 653 75 10 1 2 4 6 557
wally79 wrote: » 75+10+(4*2)=93*6=558-1=557 4 4 6 7 8 50 367
Wanderer2010 wrote: » 6-(4/4)=5 (50-5)*8=360+7=367 25 9 2 4 6 7 813
wally79 wrote: » 25*4=100-7-2=91*9=819-6=813 3 4 5 7 9 25 664
Wanderer2010 wrote: » 25*3*9=675-7-4=664 8 5 1 9 2 7 543
wally79 wrote: » (7*9)+5=68*8=544-1=543 2 3 6 7 8 25 444
Clauric wrote: » 7 + 8 + 3 = 18 18 * 25 = 450 450 - 6 = 444 QED Numbers: 1, 3, 5, 5, 7, 9 Target: 852
Wanderer2010 wrote: » 6 8 1 3 9 8 793
Niska wrote: » (8 + 3 ( * 8 = 88 *9 = 792 +1 = 793 ======================= 2, 4, 5, 8, 9, 50 Target: 652
Wanderer2010 wrote: » 50 7 4 9 1 3 622
Niska wrote: » 50 + 7 + (4 * 3) [12] = 69 *9 = 621 + 1 = 622 =============== Aside, quick-tip: If there is a 9 in the problem: A number is divisible by 9 if the sum of it's digits is divisible by 9. If the sum is not divisible by 9, you can still use the sum to see how far away the target is from 9. Eg: 622 -> 6 +2 +2 = 10 - not divisible by 9, but just 1 away. So we know 622 -1 is divisible by 9. So 622 -1 = 621. 6 + 2 +1 = 9. (621 / 9 = 69) Ex2 - 754 -> 7 +5 +4 = 16 (Not divisible, but 2 away from 18 which is) so 754 + 2 = 756 (7 + 5+ 6 = 18, divisible by 9. 756 / 9 = 84) =============== 2,5, 9, 25, 50, 100 target: 725
Wanderer2010 wrote: » 8 6 2 2 10 7 503
Niska wrote: » No 9! (6 * 10) = 2 = 62 *8 = 496 +7 = 503 ===================== 2,6,6, 8, 10, 50 target: 922
wally79 wrote: » 50+(6*8)-6=92*10=920+2=922 3 3 5 6 9 25 711
Niska wrote: » =============== Aside, quick-tip: If there is a 9 in the problem: A number is divisible by 9 if the sum of it's digits is divisible by 9. If the sum is not divisible by 9, you can still use the sum to see how far away the target is from 9. Eg: 622 -> 6 +2 +2 = 10 - not divisible by 9, but just 1 away. So we know 622 -1 is divisible by 9. So 622 -1 = 621. 6 + 2 +1 = 9. (621 / 9 = 69) Ex2 - 754 -> 7 +5 +4 = 16 (Not divisible, but 2 away from 18 which is) so 754 + 2 = 756 (7 + 5+ 6 = 18, divisible by 9. 756 / 9 = 84) ===============
Wanderer2010 wrote: » 8 7 2 4 6 7 754
Niska wrote: » (8 +6) * 4 = 56 +2 = 58 * (6 + 7)[13] = 754 ============================ 3, 5, 5, 7, 8, 10 Target: 478
Wanderer2010 wrote: » Hard luck on my puzzle. Im afraid I only had a single 6 in it. Here is another way around it: 7*8=56+2 = 58*(7+6) =754
Wanderer2010 wrote: » 100 8 5 4 4 1 657
Niska wrote: » Bit of a brain fart there - sorry. 100 + (8 * 4) = 132 * 5 = 660 - 4 + 1 = 657 ====================== 6, 7, 9, 10, 50, 100 Target: 589
Wanderer2010 wrote: » 6*100=600 7-(50/10)=2+9=11 600-11=589 25 6 3 7 5 4 661
Ciaran wrote: » 2 4 6 8 9 75 684