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Help needed with java number guessing game, please

marzy

Hi All,
I'm looking for any help anyone could give me for the problem below, I'm at the early stages of a Java programming course and have run into problems. I have tried debugging the errors and re-started a couple of times, but think I'm going about it completly wrong.The out-line of the program is:

Write a program which asks the user for 1 integer number between 1 and 10.
Get the computer to randomly generate a number between 1 and 10
If your number == it's number, print "you have won"
If your number < computer's number, print "Too low"
if your number > computer's number, print "Too High"
Print out both numbers

I have'nt posted any errors as there is always others leading me to believe I have made a balls of the whole thing.Also the aim is to use the java.util.Random; function.

import java.util.Random; //call the random number generator
public class Game
{
static Random generator = new Random();
public static void main (int a)

{
int b;
b = getRandomNumber(11); //no's between 0 - 10

if (value == a)
{
System.out.println ("You have WON!");
}
if (value < a)
{
System.out.println ("Too Low");
}
if (value > a)
{
System.out.println ("Too High");
}

}

private static int getRandomNumber(int b)
{
Random generator = new Random();
int value;

value = generator.nextInt( b );

}
} //end class

Please keep it as basic as possible as I don't want to be hassling people for explanations of their hopefully helpful posts

Thanks,
Marzy

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Comments

lynchie

Firstly you need to read up on passing in command line arguments at
http://java.sun.com/docs/books/tutorial/getStarted/application/index.html.

Secondly your getRandomNumber method doesnt return anything.

Thirdly you have a staic instance of Random that does nothing either.

Ri_Nollaig

Few things.

I'd say you need to check up more on scope, you have declared a variable "value" in getNumberFromUser(), this would not be visible in the main. It would need to be a global and then a static too for that to work.

change getRandomNumber(int b) to :

private static int getRandomNumber(int limit) {
   Random generator = new Random();
   return generator.nextInt(limit);
}

now just assign b (perhaps a better name?) to the result of that.

Also, your not actually reading in a number anywhere. You look like your trying to use arguments but they are stored as a String Array. Judging from the description ull need to use something like System.in

add this method:

import java.io.*;

...

private static int getNumberFromUser() {
   int input -1;
   System.out.println("Enter a number between 1 and 10");
   BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
   try {
      String userInput = br.readLine();
      try {
         input = Integer.parseInt(userInput);
         if(input < 1 || input > 10) {
            input = -1;
         }
      } catch (Exception e) {
         e.printStackTrace(); 
      }
   } catch (IOException e) {
      e.printStackTrace();
   }
   return input;
}

have your main assign 'value' to the result of that.

I'm sure you can figure out how to print the two numbers.
Also get rid of the unused variables...

marzy

Thanks for the help lads, hope to get a go at this over the weekend (if the kids let me)

Marzy

Anima

I'd use the Scanner class to read in text. Its very easy to use.

[PHP]
class HM1
{
psvm{ // not writing it all out, its the main function
Scanner input = new Scanner( System.in );
Random rand = new Random( System.currentTimeMillis() ); // will seed the random generator so you dont get the same result every time you run the program
int num1;

num1 = input.nextInt(); // will sit on this line til you enter an int

if( num1 == (rand.nextInt(11)+1) ) { // rand.nextInt(10) on its own will give you a number between (0 and 9)
System.out.println("You a winna! Ha! Ha! Ha!");
}
}
}
[/PHP]