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30-04-2012, 19:39   #1
stefanG
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Thermodynamics- particle speed

I don't know if I'm just not seeing the answer in front of me but I've been stuck on this question for a while now and any help would be greatly appreciated.

"Calculate the speed of argon atoms at standard tempeture(273.15 K) and standard pressure(1.01*10^5 Pa). You may assume that it behave as an ideal gas. The atomic mass of Argon = 40 u."

Last edited by stefanG; 30-04-2012 at 20:09.
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30-04-2012, 19:48   #2
brownacid
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First problem is your temperture is below absolute zero, you'd wanna check you took down the question right
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30-04-2012, 20:08   #3
stefanG
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My bad, I put in the minus by accident; it's suppose to be 273.15 aka absolute zero.
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01-05-2012, 18:36   #4
citrus burst
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Use this relationship

1/2*m*v^2 = 3/2*n*R*T

and rearrange to get the speed

v = sqrt(3*n*R*T/m)

You know T and m (temperature and mass) however you don't know n, the number of moles. Are you sure this is the full question? Usually they give the volume, or some other piece of information like the number of particles along with the pressure of the gas. That way you can use the relationship

PV = nRT

To figure out the missing variable, in this case n.

Unless I am missing something, thats how I would do this question

Last edited by citrus burst; 01-05-2012 at 19:02.
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