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physics question 2012 q8

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  • #2
    borrch
    Registered Users, Registered Users 2 Posts: 248 ✭✭borrch


    aarond280 wrote: »
    http://examinations.ie/archive/markingschemes/2012/LC021ALP000EV.pdf
    can anyone tell me how to answer this question, question 8, where so they get
    ( reactants:) 2.014102 + 3.016049 / 5.030151
    ( products:) 4.002603 + 1.008672 / 5.011275

    It's the values of 2/1 H + 3/1 H, check pg83 in your log tables:)

    your product values (from the periodic table - pg79) for He and H

    then ... (u)(0.018875)=mass =3.1342 x 10 (-29)

    so ... e=mc^2 is...

    E= (3.1342 x 10 -29)(2.9979 x 10 8 squared)

    Ans: 2.816878895 x 10 (-12) Joules


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