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Easy probability Question O.L.. Please?

  • 09-06-2012 2:27pm
    #1
    Registered Users, Registered Users 2 Posts: 153 ✭✭


    Would anyone be so kind and explain to me how to do this question, I don't know how to do it :/

    Helen has enough credit to download three songs from the internet, There are 7 songs that she wants.
    (i) How many different possible selections of three songs can she make?
    (ii) If there is one particular song that she wants, how many different selections now can she make??

    I know its easy.. but my minds gone blank.


Comments

  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    i) 7C3 :)

    ii) she'll always have one particular song, meaning the choice is reduced to 6C2 x 1


  • Registered Users, Registered Users 2 Posts: 5,578 ✭✭✭WarZoneBrother


    finality wrote: »
    i) 7C3 :)

    ii) she'll always have one particular song, meaning the choice is reduced to 6C2 x 1

    Yeah 7 Choose 3... Havent a notion how to do it on the calculator though ... Is there a smart way of doing this in your head?


  • Registered Users, Registered Users 2 Posts: 153 ✭✭Raeone


    What do you mean 7C3?? what do you mean by the C? :P


  • Registered Users, Registered Users 2 Posts: 2,249 ✭✭✭Bears and Vodka


    Yeah 7 Choose 3... Havent a notion how to do it on the calculator though ... Is there a smart way of doing this in your head?

    On Sharp EL-W531 it's 7, [2nd F] 5, then 3. It gives the answer of 35.

    Raeone wrote: »
    What do you mean 7C3?? what do you mean by the C? :P

    C stands for choose. 2nd F 5 on the Sharp calculator


  • Registered Users, Registered Users 2 Posts: 153 ✭✭Raeone


    First time ever seeing that, thanks :)


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  • Registered Users, Registered Users 2 Posts: 5,578 ✭✭✭WarZoneBrother


    subz3r0 wrote: »
    On Sharp EL-W531 it's 7, [2nd F] 5, then 3. It gives the answer of 35.




    C stands for choose. 2nd F 5 on the Sharp calculator

    I use a Casio.. But I will just ask teacher tomorrow going in at 9.30 to look at the stuff...


  • Registered Users, Registered Users 2 Posts: 670 ✭✭✭Naomi00


    It think that's when you use the ! button?


  • Registered Users, Registered Users 2 Posts: 661 ✭✭✭Mayo_Boy


    Do you get full marks for doing it on a calculator?


  • Registered Users, Registered Users 2 Posts: 153 ✭✭Raeone


    Mayo_Boy wrote: »
    Do you get full marks for doing it on a calculator?

    Yes!!


  • Registered Users, Registered Users 2 Posts: 153 ✭✭Raeone


    The first time I did this I did 7X6X5 = 210
    Why don't I use that way?
    How do I know when to use this C and not the first way?


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  • Closed Accounts Posts: 3,479 ✭✭✭ChemHickey


    Raeone wrote: »
    The first time I did this I did 7X6X5 = 210
    Why don't I use that way?
    How do I know when to use this C and not the first way?

    If you want to do it out in your head- don't forget to divide by 3x2x1. as 7C3 is the same as 7! divided by 3!(7-3)! So it'd be (7x6x5x4x3x2x1) divided by (3x2x1x4x3x2x1) giving you 35 selections.

    it's much faster to do it in your head if you're able!


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    Raeone wrote: »
    The first time I did this I did 7X6X5 = 210
    Why don't I use that way?
    How do I know when to use this C and not the first way?

    That's the number of permutations, not the number of combinations. If you were asked how many ways could she arrange three out of seven songs, that's what you'd do.

    Here's how to do combinations:

    IMG_20120609_164951-1.jpg

    On a Casio calculator the nCr button is the ÷ button, that is, press shift and then ÷


  • Registered Users, Registered Users 2 Posts: 2,249 ✭✭✭Bears and Vodka


    mind = blown


  • Registered Users, Registered Users 2 Posts: 63 ✭✭clairey__Ox


    I'm 99% sure this isn't on our course, I remember not being able to do it in class and the teacher said we don't need to know how to do it!


  • Registered Users, Registered Users 2 Posts: 661 ✭✭✭Mayo_Boy


    Im 99% sure that it is on our course :rolleyes:


  • Closed Accounts Posts: 6,298 ✭✭✭Namlub


    Your teacher's lying


  • Registered Users, Registered Users 2 Posts: 2,249 ✭✭✭Bears and Vodka


    Can anybody tell me how to go about doing this?

    208293.png

    208294.png

    Thank you.


  • Registered Users, Registered Users 2 Posts: 131 ✭✭grantyrs10


    of course they are on the course !!!!!!!! ha no pun intended :)

    NcR, sure it is mixed in with the Bernouilli Trials !!!!!


  • Registered Users, Registered Users 2 Posts: 131 ✭✭grantyrs10


    oops im sorry ha this isnt on ordinary level as far as I know...
    Ithought this was honours thread !


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    subz3r0 wrote: »
    Can anybody tell me how to go about doing this?

    Thank you.

    I think you'd divide the number of 4 person households in 2006 by the total number of households that year (that's the probability that a 4 person household is selected)

    and then multiply by 1000


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  • Registered Users, Registered Users 2 Posts: 46 iluvgreenday246


    Raeone wrote: »
    Would anyone be so kind and explain to me how to do this question, I don't know how to do it :/

    Helen has enough credit to download three songs from the internet, There are 7 songs that she wants.
    (i) How many different possible selections of three songs can she make?
    (ii) If there is one particular song that she wants, how many different selections now can she make??

    I know its easy.. but my minds gone blank.

    (i) 7x6x5=210 different selections

    (ii) 1x6x5=30 different selections


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    (i) 7x6x5=210 different selections

    (ii) 1x6x5=30 different selections

    This is permutations, not combinations.


  • Closed Accounts Posts: 3,479 ✭✭✭ChemHickey


    (i) 7x6x5=210 different selections

    (ii) 1x6x5=30 different selections

    If you say that, you're saying that if you downloaded song 1 before song 2 it matters, for this question you only care what song you want, not what order you want them/download them in!


  • Closed Accounts Posts: 3,479 ✭✭✭ChemHickey


    finality wrote: »
    This is permutations, not combinations.

    Finality, I don't think we should be snooping in this thread... we've a horror of a paper to worry about...


  • Registered Users, Registered Users 2 Posts: 153 ✭✭Raeone


    Thanks a million everyone. It was from the 2010 paper I think so paper it isn't on the course anymore. I understand how to do it now though!!


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    ChemHickey wrote: »
    Finality, I don't think we should be snooping in this thread... we've a horror of a paper to worry about...

    I know. :( I've been working at probability all day though. I wanted to take my mind off it...by posting about probability online.


  • Closed Accounts Posts: 3,479 ✭✭✭ChemHickey


    finality wrote: »
    I know. :( I've been working at probability all day though. I wanted to take my mind off it...by posting about probability online.

    I haven't done anything. I might do some now. Recommendations?


  • Registered Users, Registered Users 2 Posts: 63 ✭✭clairey__Ox


    Raeone wrote: »
    Thanks a million everyone. It was from the 2010 paper I think so paper it isn't on the course anymore. I understand how to do it now though!!


    I promise you, it's not on the course!


  • Registered Users, Registered Users 2 Posts: 63 ✭✭clairey__Ox


    Mayo_Boy wrote: »
    Im 99% sure that it is on our course :rolleyes:

    Namlub wrote: »
    Your teacher's lying


    Nope, it's not on it. It was on the 2010 sample paper and for non pilot schools it is not on the course this year.
    I can't speak for pilot schools but for the majority it's not on tomorrows paper, so I'm not lying :rolleyes:

    Best of luck tomorrrow!


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  • Registered Users, Registered Users 2 Posts: 153 ✭✭Raeone


    Thanks :)


  • Registered Users, Registered Users 2 Posts: 1,763 ✭✭✭finality


    It's definitely not on the OL course, I noticed that in one of the SEC circular letters. So no need to worry about this guys :)


  • Closed Accounts Posts: 6,298 ✭✭✭Namlub


    If it's seriously not on the course I don't know why I'm even bothering with sample papers because they obviously don't correspond to the syllabus, ugh.


  • Closed Accounts Posts: 2,359 ✭✭✭whiteandlight


    Which circular was that? You all seem to mixing up permutations and combinations. Permutations are on the HL course and not the ordinary but combinations are on both.

    Combinations are ways of choosing r objects from n objects when you don't care about order eg when downloading songs, it doesn't matter which you download first.

    Permutations are ways of choosing r objects from n objects when order matters eg when choosing first, second and third place in a competition.

    Only combinations are on OL and you can do them using the nCr function on your calculator.

    Eg how many committees of three can be chosen from seven people?
    7ncr3

    If one of the seven members John can not be chosen, how many committees are possible?
    There are only 6 people left to chose from but we still need three
    6ncr3

    If Mary has to be on the committee how many possible arrangements are there?
    Mary is chosen leaving 6 people to pick from but we already have one of the three positions filled so we only need two more
    6ncr2


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