help in (h= .5gt2) related que.

Femii

I have this equation h=.5g(t)2 the question is what happens to t if we doubled h?

can i say that t will be 2(t)2==> 2xtsquared? or is it .5(t)2

FISMA

In your equation, what are you doing to time?

Whatever you are doing to time, you need to do to the "2."

Femii

Its not number 2 its time squared i inly want the relation between the time and h, wt would happen to the time if we doubled the h

FISMA

Sorry for the misread. You have to learn how to play the constant game.

What you have given us is a kinematic equation that has been simplified by your initial conditions.

You're going to try and remove everything that is constant from the equation. In such a question, you will hopefully be left with just the two variables. Then, you can determine the relationship between the left and right hand side.

The idea is that you take out as many constants and the equal sign. The whole lot becomes a proportionality sign.

Kind of like E = mc²

c is a constant. c² is another constant. Take out the constant and the "=" sign and replace with a proportionality sign, which looks like a fish, or alpha (∝).

So

E = mc²

becomes

E ∝ m

Energy and mass are directly proportional.

If you double the mass, you double the Energy.

Another easier way is to see what happens when you fill in some values. How long does it take a ball to fall 10m? How long does it take to fall 20m? What do you notice about the times of flight? Did they double?

BTW - the ½ is a constant - pull it out as well.

Femii

thanks it really helped me i get it now