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Maths help

  • 16-05-2011 6:02pm
    #1
    Registered Users, Registered Users 2 Posts: 82 ✭✭


    Anyone care to help me solve the following? Lim(x-0) sinxtanx/x^2???I have reduced tan x to sinx/cosx giving me sin^2x/cosx//x^2 ..have then attempted to find the limit of sin^2x and 1/cosx//x2 and have multiplied them only to get the answer wrong..:confused:?


Comments

  • Registered Users, Registered Users 2 Posts: 927 ✭✭✭Maybe_Memories


    ted9308 wrote: »
    Anyone care to help me solve the following? Lim(x-0) sinxtanx/x^2???I have reduced tan x to sinx/cosx giving me sin^2x/cosx//x^2 ..have then attempted to find the limit of sin^2x and 1/cosx//x2 and have multiplied them only to get the answer wrong..:confused:?

    Have you studied L'Hopital's Rule?


  • Registered Users, Registered Users 2 Posts: 1,595 ✭✭✭MathsManiac


    All these kinds of questions on the LC course can be handled using the fact that the limit as x->0 of [sin(x)]/x is 1.

    In this case, group your expression as [sin(x)]/x times [sin(x)]/x times 1/cos(x), and apply the product rule for limits.

    (L'Hopital's rule is not on the LC course, so most students wouldn't know it at this level.)


  • Registered Users, Registered Users 2 Posts: 927 ✭✭✭Maybe_Memories


    All these kinds of questions on the LC course can be handled using the fact that the limit as x->0 of [sin(x)]/x is 1.

    In this case, group your expression as [sin(x)]/x times [sin(x)]/x times 1/cos(x), and apply the product rule for limits.

    (L'Hopital's rule is not on the LC course, so most students wouldn't know it at this level.)

    Ah right, sorry. I did see it in a revision book a few years ago though


  • Registered Users, Registered Users 2 Posts: 1,595 ✭✭✭MathsManiac


    Ah right, sorry. I did see it in a revision book a few years ago though

    Yeah, some do it, but I'm not sure whether it's "allowed".


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