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Derivatives in Higher Dimensions

  • 28-11-2010 2:57pm
    #1
    Closed Accounts Posts: 11,924 ✭✭✭✭


    say two functions f(x,y) and g(x) are differentiable at a =(5,6) for example and f(a) respectively for f:R^2 -> R and g:R->R
    Using the chain rule and jacobian matrices to get the derivative composition, i've ended up with a 1x2 matrix. however, is the derivative at a, the product of their jacobians or the product times some vector h with ||h|| -> 0

    eg (2 5) = the product of their jacobians and h =(h,k)

    is the derivative (2 5) or 2h + 5k (multiplying out the vector by the jacobian product)?


Comments

  • Registered Users, Registered Users 2 Posts: 1,082 ✭✭✭Fringe


    The chain rule gives g'(f(a))f'(a). g'(f(a)) and f'(a) are the corresponding Jacobians. Multiply them together and you get the derivative. You can think of h as the direction when you look at the directional derivative.


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