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Curl of Curl Identity Proof

  • 21-08-2010 3:40pm
    #1
    Registered Users, Registered Users 2 Posts: 156 ✭✭


    Hi, does anyone know how to prove the identity that

    curl(curl ) A = grad(divA) - grad(grad A)

    I know how to do it in cartesians or in given coordinates but how do I prove it generally. I googled it and stuff but can't find anything, can anyone point me in the right direction please?? Thanks.


Comments

  • Registered Users, Registered Users 2 Posts: 2,149 ✭✭✭ZorbaTehZ


    Ignore the del operator and focus on proving [latex]A \times (B\times C) = B(A\cdot C) - C(A\cdot B)[/latex] keeping in mind what does and does not commute. It's usually called the vector triple product if you want to look it up.


  • Registered Users, Registered Users 2 Posts: 156 ✭✭MoogPoo


    Well I get the vector triple product with vector product and scalar product, but how does that all relate to curl, div and grad?
    Sorry I'm still fairy new to those operations.


  • Registered Users, Registered Users 2 Posts: 2,149 ✭✭✭ZorbaTehZ


    Because from definition, you have:

    [latex]\textrm{grad} \ F=\nabla F[/latex]
    [latex]\textrm{div} \ F=\nabla \cdot F[/latex]
    [latex]\textrm{curl} \ F=\nabla \times F[/latex]


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