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biology question

  • 25-06-2010 8:06pm
    #1
    Registered Users, Registered Users 2 Posts: 20


    Twenty five colonies grew in nutrient agar from 1.0 ml of sample withdrawn from a solution diluted to 10-5 in a standard plate count procedure. How many cells were in the original sample?

    Anyone no how to work this out?
    thanks!


Comments

  • Moderators, Recreation & Hobbies Moderators, Science, Health & Environment Moderators, Technology & Internet Moderators Posts: 93,572 Mod ✭✭✭✭Capt'n Midnight


    by 10-5 do you mean 10E-5 / 1 in 100,000 dilution ?


    No idea since the cells could be clumped :p
    but you could count the colony forming units by multiplying back the dilutions

    if there are 25 per ml then at the previous 1:10 dilution there were 250 per ml


  • Closed Accounts Posts: 2,980 ✭✭✭Kevster


    She must mean 10^-5? In that case, the answer would be 2,500,000 cells? If it was a 10^-5 dilution, that's 1-in-100,000. You just multiply this by 25 to get the answer I think.

    Kevin


  • Moderators, Regional East Moderators Posts: 23,238 Mod ✭✭✭✭GLaDOS


    Kevster wrote: »
    She must mean 10^-5? In that case, the answer would be 2,500,000 cells? If it was a 10^-5 dilution, that's 1-in-100,000. You just multiply this by 25 to get the answer I think.

    Kevin
    Yeah, it's 25 x 10^5 = 2,500,000. However that's not cells, it's colony forming units per ml (cfu/ml) as Capt'n said.

    Cake, and grief counseling, will be available at the conclusion of the test



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