Chemistry Q

theowen

Question is-propanone can be syntisisedfrom propene in two steps, with propanol teh product of the firt step.

Anyway know where this expermint/demonstration tingy would be in the book? I vagely remember something about copper

citizenerased1

Hate that question dude

im stayin away from mechanisms and that synthy stuff!

theowen

citizenerased1 wrote: »

Hate that question dude

im stayin away from mechanisms and that synthy stuff!

You had my hopes up there:mad::p

Psychedelia

you need propan-2-ol in order to get the a ketone.
so all you've to do then is to turn the OH functional group into a double O.
that's oxisation cos its the removal of a H.
so you use sodium dichromate i think... i'll check that though

edit:

page 371 of "chemistry live":

secondary alcohols are oxidised to ketones.

using sodium dichromate and the presence of H+.

citizenerased1

Psychedelia wrote: »

you need propan-2-ol in order to get the a ketone.
so all you've to do then is to turn the OH functional group into a double O.
that's oxisation cos its the removal of a H.
so you use sodium dichromate i think... i'll check that though

i thats right i remember some oxidation and reduction in organic thing

theowen

Psychedelia wrote: »

you need propan-2-ol in order to get the a ketone.
so all you've to do then is to turn the OH functional group into a double O.
that's oxisation cos its the removal of a H.
so you use sodium dichromate i think... i'll check that though

edit:

page 371 of "chemistry live":

secondary alcohols are oxidised to ketones.

using sodium dichromate and the presence of H+.

The marking scheme says water for the conversion of propene to propanl-2 ol and sodium dichmoate and sulphuric acid for the second, while passing it over a hot copper catalyst. hmm?

Psychedelia

theowen wrote: »

The marking scheme says water for the conversion of propene to propanl-2 ol and sodium dichmoate and sulphuric acid for the second, while passing it over a hot copper catalyst. hmm?

that's right.
Water will exist as h+ and OH- ions.
the OH- ions will attack the double bond in propene.
forming(in some cases) propan-2-ol.

propan-2-ol is then oxidised by the sodium dichromate and sulphuric acid( acids bing a source of protons) to propane, i.e. loses the H.

diagrams are handier for this kind of thing..

oh and heat as ya do for the sodium dichromate reactions..

but the copper.... i have not used before...

theowen

Psychedelia wrote: »

that's right.
Water will exist as h+ and OH- ions.
the OH- ions will attack the double bond in propene.
forming(in some cases) propan-2-ol.

propan-2-ol is then oxidised by the sodium dichromate and sulphuric acid( acids bing a source of protons) to propane, i.e. loses the H.

diagrams are handier for this kind of thing..

oh and heat as ya do for the sodium dichromate reactions..

but the copper.... i have not used before...

Yeah seems to make sense. I just wasn't sure because I hadn't seen it before, which doesn't usually happen at this stage :)