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Help: VB6 wont open filepath with *.* in it?

  • 01-12-2006 12:53pm
    #1
    Morpheus
    Moderators, Society & Culture Moderators Posts: 2,688 Mod ✭✭✭✭ 


    sPath = m_strIngramFilePath & "a.*"
Open sPath For Input As #FileNumber

    this keeps getting me error 52 bad filename?

    any suggestions? i want it to open any file that appears in a folder in the following format.

    A1223434
    A12321332.ddd
    A347e8347.rty

    basically all files that appear herre will contain A as the first character, extentions are optional.

    i can DIR from command prompt using A*.* or A?*.* but not from VB code!!!

    im at a loss and would appreciate your views.

    cheers.


Comments

  • #2
    bonkey
    Registered Users, Registered Users 2 Posts: 15,443 ✭✭✭✭bonkey


    Wildcards match more than one file.

    Open allows you to open one file.

    What you need is to iterate through the filenames, presumably in a loop, and open each one individually.

    The FileScriptingObject is probably your friend here if you go read up on it.


  • #3
    Morpheus
    Moderators, Society & Culture Moderators Posts: 2,688 Mod ✭✭✭✭Morpheus


    cheers, will do.


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