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I just realised ...

ecksor · 2003-10-08 20:27:56

... my boards.ie userid is prime! and my birthday is the same as Paul Erdos

08-10-2003 8:27pm

#1

ecksor

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... my boards.ie userid is prime!

and my birthday is the same as Paul Erdos

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#2 08-10-2003 11:59pm

dod

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busy there ecksor?

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#3 09-10-2003 12:10am

ecksor

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Trying to integrate.

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#4 09-10-2003 9:50am

Syth

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How do you find out your userid?

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#5 09-10-2003 9:58am

jd

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easy way-click on the profile button under one of your posts..
eg for you url will be
http://www.boards.ie/vbulletin/member.php?s=&action=getinfo&userid=17826

so userid=17826

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#6 09-10-2003 10:07am

dod

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Damn the number 3 which causes my userid not to be prime.

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#7 09-10-2003 3:29pm

charlieroot

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It is but it's not a cool prime, ie it isn't a sum of two squares because its not 1 mod4

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#8 31-10-2003 11:45am

ecksor

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It is a Gaussian prime and that's good enough for me.

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#9 02-11-2003 12:56pm

Capt'n Midnight

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3 x 3 x 5 x 383 . Well at least it's the sum of two primes...

383 is the sum of the first 3, three-digit palindromic primes: 101, 131 and 151.
The smallest prime which can be represented as sum of a prime and its reverse (241 + 142 = 383).

cf. http://primes.utm.edu/curios/

PS - Prime check on http://primes.utm.edu/curios/includes/file.php?file=primetest.html

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#10 02-11-2003 1:12pm

tribble

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I'm prime too

userid 2689

At least thets what Coolmaths tells me.

Pity it doesn't tell me what a prime number is though...

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#11 02-11-2003 1:17pm

ecksor

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In short, any natural number that has only two factors in the natural numbers, itself and 1.

http://primes.utm.edu/glossary/page.php?sort=Prime
http://mathworld.wolfram.com/PrimeNumber.html

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#12 02-11-2003 6:55pm

charlieroot

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Being *really* pedantic about it, the proper definition for a prime is an element of a ring A such that if p|a*b, then p|a and/or p|b. The natural numbers don't form a ring and if you were to give the definition with respect to Z, the integers, as you have just done then you are really giving the definition of an irreducible element and not necessarily a prime, however when considering the ring Z, all irreducibles are prime - this is not always the case. Take for example the ring of integers in the field Q(sqrt[-5]).

6 = (1-sqrt[-5])(1+sqrt[-5])

3 | 6 but 3 does not divide 1-sqrt[-5]. Hence 3 is irreducible but not prime.

Noel.

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#13 02-11-2003 7:08pm

tribble

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I like ecksor's answer

charlieroot - you're talking to someone who passes uni. c.s./chem maths by hiring an Iraqi immigrant (sp?) for 6 hours in two 3 hour blocks to hypersaturate my brain with turnkey solutions for all possible questions on the maths paper. I don't goto maths lectures anymore - they depress me.
While I'm proud of being able to do a year of maths in 6 hours I'm ashamed to say I don't understand one dot

Oh well - could be worse - I mean, I hear some people actually enjoy maths - freaks

tribble

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#14 03-11-2003 10:00pm

sceptre

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Hmmm, /me is not prime.

My userID is prime if you divide it by 74 first though and that's close enough for government work:)

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#15 03-11-2003 11:29pm

Tree

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i is also prime
[notes the number of maths heads w/ primes.....]

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#16 04-11-2003 5:48pm

Capt'n Midnight

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Originally posted by Tree
i is also prime
[notes the number of maths heads w/ primes.....]

No I don't think the square root of minus one is a prime

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