Hey people , need some help with this Question if anyone is willing.

Ok heres the sum ∫ Sin x ( 1+ √ (cosx) )^2 dx

So my guess is : u = Sinx and dv = ( 1+ √ (cosx) )^2 dx

Then ..... du = cosx v = ∫ ( 1+ √ (cosx) )^2 dx

*tried expanding it to... *

v= ∫ ( 1 +2√ (cosx ) + cos x ) dx

v = x + "?" + sinx

Its the v part i cant figure out ... is it a double integration by parts question?

Any help much appreciated...

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