Eigen vector problem

[zaraba]

Right, this is driving me up the walls...

0.981 , 0.019
0.019 , 0.981

is a transition matrix, I want to get to the eigenvalues and vectors.
Now I'm getting that 1 and 0.962 are the eigenvalues and that
-0.70711 , 0.70711
0.70711 , 0.70711
are the eigenvalues, but those don't make sense economically (at least I don't think they do)
as

(p(a)) = c1 (-0.70711).(1) + c2 (0.70711).962
(p(b)) = ....(.70711).........+.....(0.70711)

leads to a p(a) = p(b) = .5, which is not correct

[zaraba]

Its grand.
Transition matrix was wrong. Stupid decimal places...

[alan4cult]

If you don't mind me asking what were you using this matrix for? What are p(a) and p(b)? Is it economics?

[zaraba]

Yeah, its to calculate the expected probabilitiy of a future state.