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Inbox · 10-08-2012, 23:22

Hi, can someone show me the steps for,

integrate 1/√x

Thanks

**Timbuk2** · 10-08-2012, 23:38

$\frac{1}{\sqrt{x}} = x^{-\frac{1}{2}}$

$\int{ x^{-\frac{1}{2}}} =\displaystyle{\frac{x^{\frac{1}{2}}}{\frac{1}{2}} = 2\sqrt{x}}} c$ where c is a constant

Inbox · 11-08-2012, 15:26

Cheers, thank you.

10-08-2012, 23:22	#1
Inbox Registered User Join Date: May 2010 Posts: 553 Adverts \| Friends	Quick integration Q Hi, can someone show me the steps for, integrate 1/√x Thanks

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10-08-2012, 23:38	#2
Timbuk2 Moderator Join Date: Oct 2005 Posts: 7,183 Adverts \| Friends Mod: Google Earth, Learning to Drive, Leaving Cert, The Graduates	$\frac{1}{\sqrt{x}} = x^{-\frac{1}{2}}$ $\int{ x^{-\frac{1}{2}}} =\displaystyle{\frac{x^{\frac{1}{2}}}{\frac{1}{2}} = 2\sqrt{x}}} c$ where c is a constant

11-08-2012, 15:26	#3
Inbox Registered User Join Date: May 2010 Posts: 553 Adverts \| Friends	Cheers, thank you.