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maths past paper question

  • 18-02-2012 6:20pm
    #1
    Registered Users Posts: 4


    hi can somebody please explain the solution to this question from 2008 paper 1 c. In particular where has the 2.04 come from?

    Walter wishes to pay off his loan in equal instalments at the end of the first
    and second year. The rate remains at 4% per annum compound interest.
    􀀢 How much would he need to repay, at the end of each year, to clear his
    loan after two years? Give your answer correct to the nearest cent.

    Solution:

    Let the equal instalment be x
    P Year 1 = €5000
    P Year 2 = €5000 × 1·04 - x = €5200 -x
    P Year 3 = (€5200 -x) × 1·04 = x Final payment
    (€5200 - x) x 1·04 = x
    €5408 - 1.04x = x
    €5408 = 2.04x
    x = €5408/ 2.04 = €2650.98


Comments

  • Registered Users Posts: 484 ✭✭brownacid


    x +1.04x = 2.04x


  • Registered Users Posts: 4 alfamale


    brownacid wrote: »
    x +1.04x = 2.04x

    That's the bit i don't understand. :(


  • Registered Users Posts: 19 gerardo1982


    As the previous poster said:

    x + 1.04x = 2.04x

    The x on it's own is the same as 1x.

    You could also write it this way:

    1x +1.04x = 2.04x


  • Registered Users Posts: 4 alfamale


    thanks, easy when you know.


  • Registered Users Posts: 19 gerardo1982


    It's the same with most things in life, anyway good luck with your studies.


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